Y=0.5x^2-12x+120

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Solution for Y=0.5x^2-12x+120 equation: 



=0.5Y^2-12Y+120

We move all terms to the left:

-(0.5Y^2-12Y+120)=0

We get rid of parentheses

-0.5Y^2+12Y-120=0

a = -0.5; b = 12; c = -120;
Δ = b2-4ac
Δ = 122-4·(-0.5)·(-120)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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